Question

Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

Answer 1

i get

1701*3^(1/3)

but might wanna double check

Answer 2

1701 :D

Answer 3

:)) thanks!

Answer 4

ok so

the rule is this

a+r^0 + a r ^1 + ar^2

1 2 3

your a is 7

so for your 9th term is
ar^8

7*(r)^8=45927

Solve for r I got 3

plug back into 6th

a r^5

7* 3^5

right?

Answer 5

double check tho I never done these before I just did a quick wiki search :P

Answer 6

wait I have but very briefly maybe like 20 minutes in my calc 2 class :P