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Given the following chemical equation, how many grams of carbon monoxide gas are produced when 50.0 grams of silicon dioxide reacts with 36.0 grams of carbon?
SiO2 (s) + 3C (s) SiC (s) + 2CO (g)

56.0 grams

168 grams

46.6 grams

67.3 grams

Question

3 points  	Save  
 	
Given the following chemical equation, how many grams of carbon monoxide gas are produced when 50.0 grams of silicon dioxide reacts with 36.0 grams of carbon?
SiO2 (s) + 3C (s)  SiC (s) + 2CO (g)
 
		
56.0 grams
 		
168 grams
 		
46.6 grams
 		
67.3 grams

anonymous · Answer

the limiting reagent in this reaction is C. The mole ratio of C: CO is 3: 2, thus the moles of C from 36g = 36/12 = 3.
moles of CO = 2
mass of CO  produced = 2(12+16)
                                          = 56g

anonymous · Answer

So where does 36 come in for the final answer??