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Solve: (x+5)/(x^2+x)=1/(x^2+x)-(x-6)/(x+1)
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@jim_thompson5910 @dpaInc @Mertsj
\[\frac{x+5}{x(x+1)}=\frac{1}{x(x+1)}-\frac{x-6}{x+1}\]
Common denominator is x(x+1). Clear fractions by multiplying by it:
\[x+5=1-x(x-6)\]
\[x+5=1-x^2+6x\] \[x^2-5x+4=0\] \[(x-4)(x-1)=0\] x=4 or x=1
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Thank you so much! =)
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