The number of solutions that are possible for the inequality \[\left[ x-5 \right] +\left| x -1\right|<2\] is
[x-] ??
sorry it is -5
and what is [] <--- is it floor or ceil??
or absolute value??
absolute value
you ment this right/? \[|x−5|+|x−1|<2\]
yes u r correct 0 solution
but how?
is |x-5| + |x-1| ever less than zero??
sorry .. ever less than 2?? or |x-5| + |x-1| - 2 less than zero ... check the graph
so...... the sign should be > to have solution is it...
No ... you just need to find a point for which the above in equality is true eg 3 < x < 4 3.5 is greater than 3 and less than 4 ... so this is true ... so this is solution
can u explain it more..... plzzzz
You just need to find the numbers that satisfy the given condition.
i mean you have to find that numbers for which the given condition is true. for eg: 1 > x > 2 (find a number that is less than and greater than two ... find it's solution
plzzz help !
i did nt understand
plzz help any one plz!!
See the attached graph to see that |x-5| + | x-1| is always bigger than 2. There are no solutions. If this does not convince you try to consider three cases x <1 1< x < 5 x > 5 In each case try to solve it. I will do the first case for you if x< 1 the inequality becomes 5-x + 1 -x < 2 -2 x < -4 x > 2 contradiction with the face that x<1 Mimic for the remaining cases and conclude.
@eliassaab the next i got x<4
1 < x < 5 |x-5| + | x-1| < 2 5- x + x -1 < 2 4 < 2 contradiction. Do the last case.
i f x > 5 |x-5| + | x-1| < 2 x-5 + x -1 < 2 2 x < 8 x < 4 but x > 5 contradiction.
so......
Did you understand it?
yes
then ................
You are done. You showed that all cases lead to contradictions. So there are no solutions. Did you get it now?
ok
yw
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