Question

Simplify f(x)+g(x) when f(x)=-6/(x+3) and g(x)= 2/x

Answer 1

This is my last one! Would you mind walking me through this one last time? @jim_thompson5910

Answer 2

In order to add the fractions, you need to make all the denominators equal to the LCD. Once you do that, you can add the fractions.


\[\Large f(x)+g(x)\]


\[\Large -\frac{6}{x+3}+\frac{2}{x}\]


\[\Large -\frac{6x}{x(x+3)}+\frac{2}{x}\]


\[\Large -\frac{6x}{x(x+3)}+\frac{2(x+3)}{x(x+3)}\]


\[\Large -\frac{6x}{x(x+3)}+\frac{2x+6}{x(x+3)}\]


\[\Large \frac{-6x+2x+6}{x(x+3)}\]


\[\Large \frac{-4x+6}{x(x+3)}\]


\[\Large \frac{-4x+6}{x^2+3x}\]



So \[\Large f(x)+g(x)=\frac{-4x+6}{x^2+3x}\]

Answer 3

Thank you so incredibly much again! You have no idea how much I appreciate you walking me through this stuff, thank you =)

Answer 4

you're very welcome :)