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Mathematics
OpenStudy (anonymous):

How many permutations of 4 letters can be made out of the letters of the word "EXAMINATION"?

6 years ago
OpenStudy (anonymous):

$\frac{ {_{11}P_{4}} }{2!*2! } = 1980$

6 years ago
OpenStudy (anonymous):

"EXAMINATION" Total 11 letters, 1E,1X,2A,1M,2I,2N,1O,1T, the answer is the coefficient of $$x^4$$ in $4! (1+x)^5 (1+x+\frac {x^2}{2!})^3$ which is $$2454$$

6 years ago
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