a model rocket is launched from ground level into the air. its height is y, in feet, after x seconds can be represented by the equation y=160x-5x sq. what is the elapsed time in seconds, from the time the rocket is launched until it reaches ground level again?

Question

asnaseer · Answer

you are given:$$y=160x-5x^2$$where y represents the height and x represents the time in seconds.
when the rocket in on the ground, what do you think the value of y will be?

asnaseer · Answer

remember y represents the height from the ground, so when the rocket is on the ground then y=?

anonymous · Answer

0

asnaseer · Answer

correct, so we can now substitute y=0 into the equation you were given to get:$$0=160x-5x^2=5x(32-x)$$

asnaseer · Answer

do you know how to solve this for x now?

anonymous · Answer

yes thanks

asnaseer · Answer

yw