Mathematics OpenStudy (anonymous):

How do I find the common ratio of the sequence. â€“80, â€“40, â€“20, â€“10, . . . Parth (parthkohli):

The current term over the previous term is the common ratio. Parth (parthkohli):

$$\Large \color{MidnightBlue}{\Rightarrow r = {r_n \over r_{n - 1}} }$$ OpenStudy (savvy):

in a GP, the first term is 'a' 2nd term is 'ar' 3rd term is 'a(r^2)' and so on....nth term is a[(r)^(n-1)]...... so clearly any term divided by its previous term wud give you the value of 'r'...r is the common ratio... Parth (parthkohli):

And I meant an not rn

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