OpenStudy (anonymous):

factor completely p^4-18p+81

6 years ago
OpenStudy (anonymous):

is this what you are looking for... http://www.wolframalpha.com/input/?i=factor+p%5E4-18p%2B81 ?

6 years ago
OpenStudy (pfenn1):

@johnboydbooks, Are you certain that you copies the original expression correctly> Are you sure the first term doesn't contain a p^2 or perhaps the second term?

6 years ago
OpenStudy (anonymous):

Can you try to factor our p\[p ^{4}-18p+81?\] just like normal equation?

6 years ago
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