Mathematics

OpenStudy (anonymous):
Help please!
If g(x)=log_7x, find g(1/49).

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OpenStudy (anonymous):
what is the underscore supposed to represent?

OpenStudy (anonymous):
Just that 7 is lower.

OpenStudy (anonymous):
base 7 you mean?

OpenStudy (anonymous):
Yeah, my bad.

OpenStudy (anonymous):
g(1/49) = \[\log_{7} (1/49)\]

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OpenStudy (anonymous):
uh no not quite, you can do it without one.

OpenStudy (anonymous):
\[\log_{7} (1) - \log_{7} (49)\]

OpenStudy (anonymous):
can you do the rest?

OpenStudy (anonymous):
Yea, thanks!

OpenStudy (anonymous):
True. Thanks

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OpenStudy (anonymous):
yea but you can't always rely on a calculator. especially in university, you don't get to use one anyway.

OpenStudy (netlopes1):
if your function is \[g(x)=\log_{7}x\] and you want g(1/49) do this

OpenStudy (anonymous):
he already has the answer^ -.-.

OpenStudy (anonymous):
stop giving me notifications

OpenStudy (netlopes1):
\[g(1/49)=\log_{7}{1/49} \rightarrow \log_{7}{7^{-2}} \rightarrow -2.\log_{7}{7} \rightarrow \]

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OpenStudy (netlopes1):
And finally, \[g(1/49)=-2.1 \rightarrow g(1/49) = -2\]

OpenStudy (anonymous):
Thanks! Wish I could give another medal.

OpenStudy (netlopes1):
Thanks!! If you need, i will for here, ok?