Question

Help please!
If g(x)=log_7x, find g(1/49).

Answer 1

what is the underscore supposed to represent?

Answer 2

Just that 7 is lower.

Answer 3

base 7 you mean?

Answer 4

Yeah, my bad.

Answer 5

g(1/49) = \[\log_{7} (1/49)\]

Answer 6

uh no not quite, you can do it without one.

Answer 7

\[\log_{7} (1) - \log_{7} (49)\]

Answer 8

can you do the rest?

Answer 9

Yea, thanks!

Answer 10

True. Thanks

Answer 11

yea but you can't always rely on a calculator. especially in university, you don't get to use one anyway.

Answer 12

if your function is \[g(x)=\log_{7}x\] and you want g(1/49) do this

Answer 13

he already has the answer^ -.-.

Answer 14

stop giving me notifications

Answer 15

\[g(1/49)=\log_{7}{1/49} \rightarrow \log_{7}{7^{-2}} \rightarrow -2.\log_{7}{7} \rightarrow \]

Answer 16

And finally, \[g(1/49)=-2.1 \rightarrow g(1/49) = -2\]

Answer 17

Thanks! Wish I could give another medal.

Answer 18

Thanks!! If you need, i will for here, ok?