Mathematics
OpenStudy (anonymous):

Solve the attached problem...

OpenStudy (anonymous):

OpenStudy (anonymous):

Possible answers are .0106 .2721 .0047 .1209 .7558

OpenStudy (anonymous):

You can use the Pascal's triangle to solve this or Binomial coefficient which is $(x+a)^{n} = \left(\begin{matrix}n \\ 0\end{matrix}\right)x ^{n}+\left(\begin{matrix}n \\ 1\end{matrix}\right)x ^{n-1}a ^{1}$

OpenStudy (anonymous):

How would I use pascals triangle for this problem?

OpenStudy (anonymous):

The pascal's triangle go like this http://en.wikipedia.org/wiki/File:PascalTriangleAnimated2.gif

OpenStudy (anonymous):

you count the number 1 outside for the power that you have. For example in the picture if you count the number 1 on the outside there are 5. That's mean the problem is $(x+a)^{5}$

OpenStudy (anonymous):

what would the x and a be for my question though?

OpenStudy (anonymous):

OpenStudy (anonymous):

let's set up the Pascal triangle first.

OpenStudy (anonymous):

but then i only got 1, which is not one of my choices

OpenStudy (anonymous):

oh... so i am not necessarily doing it to the fifth power

OpenStudy (anonymous):

Yes 1 is incorrect since the question asks you to Expand you cannot add them together.

OpenStudy (anonymous):

Yes your is to the 10th power

OpenStudy (anonymous):

so it would be ((3/5)+(2/5))^10?

OpenStudy (anonymous):

Look at the equation (3/5 + 2/5) ^10. The other stuffs are just there to explain the "history" of the problem. They are not important right now.

OpenStudy (anonymous):

Correct!

OpenStudy (anonymous):

but that still only gets me 1 because (3/5)+(2/5)= 1 and 1^10=1

OpenStudy (anonymous):

OpenStudy (anonymous):

Try to draw the pascal triangle

OpenStudy (anonymous):

|dw:1338071183404:dw| Can you do 5 more rows? from here?