Solve the attached problem...

Possible answers are .0106 .2721 .0047 .1209 .7558

You can use the Pascal's triangle to solve this or Binomial coefficient which is \[ (x+a)^{n} = \left(\begin{matrix}n \\ 0\end{matrix}\right)x ^{n}+\left(\begin{matrix}n \\ 1\end{matrix}\right)x ^{n-1}a ^{1}\]

How would I use pascals triangle for this problem?

The pascal's triangle go like this http://en.wikipedia.org/wiki/File:PascalTriangleAnimated2.gif

you count the number 1 outside for the power that you have. For example in the picture if you count the number 1 on the outside there are 5. That's mean the problem is \[(x+a)^{5}\]

what would the x and a be for my question though?

your x = 3/5 and your a would be 2/5

let's set up the Pascal triangle first.

but then i only got 1, which is not one of my choices

oh... so i am not necessarily doing it to the fifth power

Yes 1 is incorrect since the question asks you to Expand you cannot add them together.

Yes your is to the 10th power

so it would be ((3/5)+(2/5))^10?

Look at the equation (3/5 + 2/5) ^10. The other stuffs are just there to explain the "history" of the problem. They are not important right now.

Correct!

but that still only gets me 1 because (3/5)+(2/5)= 1 and 1^10=1

No you don't add them because the question ask to expand.

Try to draw the pascal triangle

|dw:1338071183404:dw| Can you do 5 more rows? from here?

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