Question

Solve the attached problem...

Answer 1

Possible answers are
.0106
.2721
.0047
.1209
.7558

Answer 2

You can use the Pascal's triangle to solve this or Binomial coefficient which is \[ (x+a)^{n} = \left(\begin{matrix}n \\ 0\end{matrix}\right)x ^{n}+\left(\begin{matrix}n \\ 1\end{matrix}\right)x ^{n-1}a ^{1}\]

Answer 3

How would I use pascals triangle for this problem?

Answer 4

The pascal's triangle go like this
http://en.wikipedia.org/wiki/File:PascalTriangleAnimated2.gif

Answer 5

you count the number 1 outside for the power that you have. For example in the picture if you count the number 1 on the outside there are 5. That's mean the problem is \[(x+a)^{5}\]

Answer 6

what would the x and a be for my question though?

Answer 7

your x = 3/5 and your a would be 2/5

Answer 8

let's set up the Pascal triangle first.

Answer 9

but then i only got 1, which is not one of my choices

Answer 10

oh... so i am not necessarily doing it to the fifth power

Answer 11

Yes 1 is incorrect since the question asks you to Expand you cannot add them together.

Answer 12

Yes your is to the 10th power

Answer 13

so it would be ((3/5)+(2/5))^10?

Answer 14

Look at the equation (3/5 + 2/5) ^10. The other stuffs are just there to explain the "history" of the problem. They are not important right now.

Answer 15

Correct!

Answer 16

but that still only gets me 1 because (3/5)+(2/5)= 1 and 1^10=1

Answer 17

No you don't add them because the question ask to expand.

Answer 18

Try to draw the pascal triangle

Answer 19

Can you do 5 more rows? from here?