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Mathematics

OpenStudy (anonymous):

Factor: 6(x^2 - 4x + 4)^2 + (x^2 - 4x + 4) - 1

OpenStudy (anonymous):

Look at the one in parentheses (x^2-4x+4) they can be written as (x^2-2)

OpenStudy (anonymous):

Huh

OpenStudy (anonymous):

Do you mean (x-2)^2

OpenStudy (anonymous):

Yes sorry I misplaced the ^2

OpenStudy (anonymous):

I don't understand how to factor these

OpenStudy (anonymous):

If you simplify you will get \[3+6 (x-2)^4-4 x+x^2= 9 - 196 x + 145 x^2 - 48 x^3 + 6 x^4 \]

OpenStudy (anonymous):

\[6(x^2-4x+4)^2)+(x^2-4x+4)-1\\(2(x^2-4x+4)+1)(3(x^2-4x+4)-1)\\(2x^2-8x+9)(3(x^2)-4x+4)-1)\\(2x^2-8x+9)(3x^(2)-12x+12-1)\\(2x^2-8x+9)(3x^2-12x+11)\\ \]

OpenStudy (anonymous):

@Luis_Rivera Hey i don't understand, can you show me on Twiddla please?

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