Uncategorised question #3
The total cost for 88 adult tickets was $\$*293*$. Because the printing machine was not functioning well, the first and the last digits of the 5-digit number were missing. If the cost for each ticket is $P, where P is an integer, find the value of P

Question

experimentx · Answer

so the first and the last number were same??

anonymous · Answer

This is a divisibility problem.

callisto · Answer

@experimentX It didn't mention..

anonymous · Answer

147

anonymous · Answer

Very easy actually, do you want me to post the solution?

pfenn1 · Answer

Not to be a pain but @FoolForMath, we're not supposed to just give the answer, are we?

anonymous · Answer

Not in general but @callisto doesn't always want full solution.

pfenn1 · Answer

Oh, special case, eh?

kinggeorge · Answer

Your solution wouldn't happen to give $*293*$ numbers such that it's divisible by 11 would it?

kinggeorge · Answer

And force $93*$ to be divisible by 8.

anonymous · Answer

For *293* to be divisible by 88 it must be divisible by 8 and 11

Thus 93* is divisible by 8 the last digit must be 6 and *2396 and the similarly the first digit must  be 1 hence 12396 divide by 88 you will get 147.

experimentx · Answer

89232

kinggeorge · Answer

Ah Ha! I knew it.

experimentx · Answer

mistake 12936

anonymous · Answer

@pfenn1: That rule is generally intended for answer snipers and users who are just looking for answers and for cases like someone is trying to explain a concept and someone else come by and drop the answer due to this the OP left ruining the teaching experience of that user concerned.

Once you spend time here you will know who wants answer and who wants to understand the problem

For example you may or may not post full solution in Fool's problem of the day :)

pfenn1 · Answer

Thanks for explaining that @FoolForMath.

callisto · Answer

@FoolForMath Thanks!!! I understand that now :)

Sorry everyone. I don't mean to just get the answers, but I really want to know how to solve these questions. Thus, numerical answers without explanations won't help much, maybe just a 'hint' for me 
(Actually, I don't have to do these questions. It's just for my interest only)

Thank you for all your help!!!

experimentx · Answer

haha ... easiest method :D

for i = 1:9
    for j=0:9
        k = i*10000 + 2930 + j;
        if mod(k, 88) == 0
            disp(k)
        end
    end
end

callisto · Answer

programming?

experimentx · Answer

haha cheating!!

callisto · Answer

I don't expect to use a computer :P

experimentx · Answer

well ... bad for me :(