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Mathematics
When doing trig, I came across this puzzler: http://mathb.in/433 Why is this so? W|A confirms: http://bit.ly/JmEk6p
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Secant is the reciprocal function of cosine. So, if you take the secant of both sides, you get x = sec(cos^-1(1/x)) Since sec = 1/cos; x = 1/cos(cos^-1(1/x)) = 1/(1/x) = x
That's kind of a non-rigorous way of showing it, I guess. :P
\[y=cosx\] \[x=\cos^{-1}y \] \[1/y = 1/cosx = secx\] \[\sec^{-1} 1/y = x\] so there comes your ans wer
|dw:1338092907462:dw| In the triangle \[\sec y=\frac{x}{1}\] \[\cos y=\frac{1}{x}\]
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