Question

I need double checking.

http://i45.tinypic.com/jqjoep.jpg

I got the answer "1"... need someone to make sure if that's right.

Answer 1

I'm getting 0.

Answer 2

Interesting, gotta figure out what I did wrong.

Answer 3

\[\frac{x^2-1}{(x-2)(x+1)}-\frac{(x-1)(x+1)}{(x-2)(x+1)}\]\[=\frac{x^2-1}{(x-2)(x+1)}-\frac{x^2-1}{(x-2)(x+1)}=\frac{x^2-1-(x^2-1)}{(x-2)(x+1)}\]\[=\frac{0}{(x-2)(x+1)}=0\]

Answer 4

Thanks, appreciate it.

Answer 5

You're welcome.