Mathematics OpenStudy (anonymous):

I need double checking. http://i45.tinypic.com/jqjoep.jpg I got the answer "1"... need someone to make sure if that's right. OpenStudy (kinggeorge):

I'm getting 0. OpenStudy (anonymous):

Interesting, gotta figure out what I did wrong. OpenStudy (kinggeorge):

$\frac{x^2-1}{(x-2)(x+1)}-\frac{(x-1)(x+1)}{(x-2)(x+1)}$$=\frac{x^2-1}{(x-2)(x+1)}-\frac{x^2-1}{(x-2)(x+1)}=\frac{x^2-1-(x^2-1)}{(x-2)(x+1)}$$=\frac{0}{(x-2)(x+1)}=0$ OpenStudy (anonymous):

Thanks, appreciate it. OpenStudy (kinggeorge):

You're welcome.

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