displacement time equation of a particle moving along x-axis is x=20+t3-12t.
a)find velocity of particle at time t=0
b)state whether the motion is uniformly acceleration or nt.
c)find position of the particle when v=0.

Question

displacement time equation of a particle moving along x-axis is x=20+t3-12t.
a)find velocity of particle at time t=0
b)state whether the motion is uniformly acceleration or nt.
c)find position of the particle when v=0.

apoorvk · Answer

if that^ is the equation of the displacement, how would you get the equation for velocity?

apoorvk · Answer

wrt 'time' ofcourse.

anonymous · Answer

"Substitute" the value of "t" and find.

anonymous · Answer

Hint for part (a): $v=\frac{dx}{dt}$
Hint for part (b): $a=\frac{dv}{dt} = \frac{d^2x}{dt^2}$.  If this is a function of time, then it is not constant.
Hint for part (c): What $t$ values satisfies this condition?

anonymous · Answer

v=dx/dt

anonymous · Answer

Sorry. @yakeyglee is absolutely correct. Follow his steps and ur answer is done

anonymous · Answer

as v=0,we 0=3t2-12

anonymous · Answer

am i right.

anonymous · Answer

Yeah, perfect @Ruchi.

anonymous · Answer

So, we get|dw:1338103103383:dw|