A light rope is fixed at one end of a wooden clamp on the ground passes over a branch and hangs on the other side. It makes an angle 30 degrees with the ground. A man weighing 60 kg wants to climb up the rope. The wooden clamp can come out of the ground if an upward force greater than 360N is applied. Find the max ace in the upward direction with which the man can climb safely. Neglect friction at the tree branch. Take g=10m/s^2

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if the clamp is taken as the system the forces on it should be: Tsin30+normal force on it-mg but the solution has just Tsin30=tension=360N why is that?

@Vincent-Lyon.Fr

Why did you close that question? If you want people to contribute, leave it as 'open'.

You have to work out the vertical component of the tension in the cable and that's it.

@Vincent-Lyon.Fr That is exactly where I'm stuck if the clamp is taken as the system the forces on it should be: Tsin30+normal force on it-mg but the solution has just Tsin30=tension=360N why is that?

You are not asked to write an equilibrium equation. The statement is in the wording of the problem: any vertical force greater than 360N will do the trick. You know the value of T, so work out its vertical component, and that's it.

@Vincent-Lyon.Fr you are the best....thanks

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