Mathematics OpenStudy (anonymous):

solve for x and y 2x-y=2 and y=(x-2)(x-1) OpenStudy (diyadiya):

$y=(x-2)(x-1)= x^2-x-2x+2 =x^2 -3x+2$ Plug in the equation of y in 2x-y=2 $2x-(x^2 -3x+2) =2$$2x-x^2+3x-2=2$$-x^2+5x-4=0$ OpenStudy (diyadiya):

Can you solve this quadratic equation ? OpenStudy (anonymous):

i tried using the formula to get the value of x but i get math error OpenStudy (diyadiya):

You can do it without using a calculator :D OpenStudy (anonymous):

im not very good at factoring thats why i use the formula OpenStudy (diyadiya):

Factorise -x^2+5x -4 =0 For easier calculation multiply the whole equation by -1 $$x^2-5x+4=0$$ You can use the quadratic formula to solve it $\huge x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$ OpenStudy (diyadiya):

Here ; a = 1 b = -5 c= 4 OpenStudy (diyadiya):

Plug in the values in the formula and find x When you've found out x, put the value of x in any of the equation in the question & find y tell me if you didn't understand any of the above steps OpenStudy (anonymous):

x=6.97 and -1.97 is that corret for the value of x OpenStudy (diyadiya):

No! Can you show me how you did that? OpenStudy (anonymous):

i used the formula |dw:1338122652146:dw|

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