solve for x and y
2x-y=2 and
y=(x-2)(x-1)

Question

solve for x and y
2x-y=2 and
y=(x-2)(x-1)

diyadiya · Answer

$$y=(x-2)(x-1)= x^2-x-2x+2 =x^2 -3x+2 $$
Plug in the equation of y in 2x-y=2

$$2x-(x^2 -3x+2) =2$$$$2x-x^2+3x-2=2$$$$-x^2+5x-4=0$$

diyadiya · Answer

Can you solve this quadratic equation ?

anonymous · Answer

i tried using the formula to get the value of x but i get math error

diyadiya · Answer

You can do it without using a calculator :D

anonymous · Answer

im not very good at factoring thats why i use the formula

diyadiya · Answer

Factorise -x^2+5x -4 =0 

For easier calculation multiply the whole equation by -1

$x^2-5x+4=0 $

You can use the quadratic formula to solve it

$$\huge x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$$

diyadiya · Answer

Here ;

a = 1
b = -5
c= 4

diyadiya · Answer

Plug in the values in the formula and find x 

When you've found out x, put the value of x in any of the equation in the question & find y
tell me if you didn't understand any of the above steps

anonymous · Answer

x=6.97 and -1.97 is that corret for the value of x

diyadiya · Answer

No!
Can you show me how you did that?

anonymous · Answer

i used the formula 
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