solve for x and y 2x-y=2 and y=(x-2)(x-1)

\[y=(x-2)(x-1)= x^2-x-2x+2 =x^2 -3x+2 \] Plug in the equation of y in 2x-y=2 \[2x-(x^2 -3x+2) =2\]\[2x-x^2+3x-2=2\]\[-x^2+5x-4=0\]

Can you solve this quadratic equation ?

i tried using the formula to get the value of x but i get math error

You can do it without using a calculator :D

im not very good at factoring thats why i use the formula

Factorise -x^2+5x -4 =0 For easier calculation multiply the whole equation by -1 \(x^2-5x+4=0 \) You can use the quadratic formula to solve it \[\huge x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\]

Here ; a = 1 b = -5 c= 4

Plug in the values in the formula and find x When you've found out x, put the value of x in any of the equation in the question & find y tell me if you didn't understand any of the above steps

x=6.97 and -1.97 is that corret for the value of x

No! Can you show me how you did that?

i used the formula |dw:1338122652146:dw|

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