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OpenStudy (maheshmeghwal9):

Please help:-----

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OpenStudy (maheshmeghwal9):

OpenStudy (maheshmeghwal9):

Answer is :-\[-\sqrt{1-x^2}\]

OpenStudy (experimentx):

cos inv 0

OpenStudy (experimentx):

is pi/2

OpenStudy (maheshmeghwal9):

ya I also did that

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OpenStudy (experimentx):

use circular inverse formula ... so it is called (i haven't tried this formula though)

OpenStudy (maheshmeghwal9):

I haven't heard of circular inverse formula!

OpenStudy (experimentx):

\[ \cos^{-1}A + \cos^{-1}B = AB + AB/(A^2+B^2) \] not sure though ... i made it up myself!!

OpenStudy (maheshmeghwal9):

but I have a formula in my book:- \[\cos^{-1} (A)+\cos^{-1} (B)=\cos^{-1} [AB-(\sqrt{1-A^2})(\sqrt{1-B^2})]\]

OpenStudy (experimentx):

Oh ... that's the formula .. sorry!!

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OpenStudy (maheshmeghwal9):

np:)

OpenStudy (maheshmeghwal9):

but u r like a teacher

OpenStudy (experimentx):

no ... not a teacher ... just stupid old guy!!

OpenStudy (maheshmeghwal9):

no! for me u r like a teacher:)

OpenStudy (maheshmeghwal9):

so what should I do now about that formula?

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OpenStudy (maheshmeghwal9):

should I use that?

OpenStudy (experimentx):

lol ... thanks for compliment :) ... though not deserved!! put the value of A=x and B=0

OpenStudy (maheshmeghwal9):

k!

OpenStudy (maheshmeghwal9):

wait a minute plz:)

OpenStudy (maheshmeghwal9):

I got |dw:1338122446950:dw|

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