Question

Please help:-----

Answer 1

Answer is :-\[-\sqrt{1-x^2}\]

Answer 2

cos inv 0

Answer 3

is pi/2

Answer 4

ya I also did that

Answer 5

use circular inverse formula ... so it is called (i haven't tried this formula though)

Answer 6

I haven't heard of circular inverse formula!

Answer 7

\[ \cos^{-1}A + \cos^{-1}B = AB + AB/(A^2+B^2) \]
not sure though ... i made it up myself!!

Answer 8

but I have a formula in my book:-
\[\cos^{-1} (A)+\cos^{-1} (B)=\cos^{-1} [AB-(\sqrt{1-A^2})(\sqrt{1-B^2})]\]

Answer 9

Oh ... that's the formula .. sorry!!

Answer 10

np:)

Answer 11

but u r like a teacher

Answer 12

no ... not a teacher ... just stupid old guy!!

Answer 13

no! for me u r like a teacher:)

Answer 14

so what should I do now about that formula?

Answer 15

should I use that?

Answer 16

lol ... thanks for compliment :) ... though not deserved!!
put the value of A=x and B=0

Answer 17

k!

Answer 18

wait a minute plz:)

Answer 19

I got