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Simplify completely quantity 4 x plus 16 over 6 I got 2 open parentheses x plus 4 close parentheses over 3
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\[4\times \frac{16}{6}\] Is this your question?
or \[\frac{4x+16}{6}\] ??
no its 4x + 16 divided by 6
the second one
Take 2 common from both the numerator and the denominator \[\frac{2(2x+8)}{2(3)}\] Cancel the 2s \[\frac{\cancel 2(2x+8)}{\cancel2(3)}=>\frac{2x+8}{3}\]
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yes thank you
2(x+8) over 3 is wrong for future people
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