Question

write an equation of the line containing the given point and parallel to the given line.
(5,-6); 3x-8y=5
if some one could please explain to me how to do this. In my mind i would turn the equation into y=mx+b form and get the slope and then go from there to get the slope intercept for the other line is this correct? y=(-3/8)x+(-5/8) then from there i would have -6=(-3/8)*5+b
y=(-3/8)x+(33/8) is this correct?

Answer 1

yes this is correct

another useful general form of equation of straight line is

y-y1 = m(x - x1)

where m = slope and (x1,y1) is a point on the line

Answer 2

for some reason my book says that the answer was 63/8 not 33/8 and I hate that form it is confusing to me.

Answer 3

now I have the equation (4,-6); 8x-5y=7

Answer 4

90l.............................

Answer 5

oops sorry that was my daughter

Answer 6

ok - lets do it again using the other equation
3x - 8y = 5
8y = -3x - 5
y = (-3/8)x - 5/8

plug in (5,-6) to general form

y + 6 = (-3/8) (x - 5)
y = (-3/8) x +15/8 - 48/8

y = (-3/8) x - 33/8

the book's wrong!

Answer 7

I agree lol but it don't think so its an ebook and just tells me that is the answer not how it got it gotta love electronics

Answer 8

yea!