Question

What is the 32nd term of the arithmetic sequence where a1 = 12 and a13 = –60 pleaseee help me figure this out!

Answer 1

arithmetic sequence is one where each term is obtained by previous by adding a constant number called the common difference
so if a is the first term the sequence is

a, a+2, a+2d, a+3d ........ where a is common difference

Answer 2

a13 the 13th term = a + 12d = -60
a1 first term = 12

so ( a + 12d) - a = -60 -12 = -72
so 12d = -72
d = -6

32nd term = a + 31d = 12 + (-6*31)

Answer 3

What is the 32nd term of the arithmetic sequence where a1 = –33 and a9 = –121 whats d in this problem

Answer 4

go on - try this one on your own!
just go through the same process as i did in the last post

a1 = -33
a9 = a1 + 8d = -121

and so on