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OpenStudy (anonymous):

(y^2-5)(9y^2-5y+1)=

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OpenStudy (anonymous):

Multiply each term on the left side by each term on the right side.

OpenStudy (anonymous):

^^^ y^2 * (9y^2 -5y + 1) + -5 * (9y^2 -5y + 1)

OpenStudy (anonymous):

[y = sqrt(5)], [y = -sqrt(5)], [y = 5/18+(1/18*I)*sqrt(11)], [y = 5/18-(1/18*I)*sqrt(11)]

OpenStudy (anonymous):

break it up first do this (y^2-5)=0 solve for y y^2=5 add 5 TBS (to both sides) y=sqrt(5) take sqrt BS ------------------ then do the other one in the perenthesis and set it to 0 9y^2-5y+1=0 it is in standard form. Use quadratic formula or comple the square [y = 5/18+(1/18*I)*sqrt(11)], [y = 5/18-(1/18*I)*sqrt(11)] has imaginary roots.

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