Question

(y^2-5)(9y^2-5y+1)=

Answer 1

Multiply each term on the left side by each term on the right side.

Answer 2

^^^ y^2 * (9y^2 -5y + 1) + -5 * (9y^2 -5y + 1)

Answer 3

[y = sqrt(5)], [y = -sqrt(5)], [y = 5/18+(1/18*I)*sqrt(11)], [y = 5/18-(1/18*I)*sqrt(11)]

Answer 4

break it up

first do this

(y^2-5)=0 solve for y
y^2=5 add 5 TBS (to both sides)
y=sqrt(5) take sqrt BS
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then do the other one in the perenthesis and set it to 0

9y^2-5y+1=0

it is in standard form. Use quadratic formula or comple the square

[y = 5/18+(1/18*I)*sqrt(11)], [y = 5/18-(1/18*I)*sqrt(11)] has imaginary roots.