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OpenStudy (anonymous):

Solve on the interval [0,2pi): 2sin^2(x)+3sinx+1=0 A. x=pi,x=2pi/3,x=5pi/3 B. x=2pi,x=pi/3 C. x=3pi/2,x=7pi/6,x=11pi/6 D. x=2pi,x=pi/4,x=5pi/4

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OpenStudy (mertsj):

factor it and set each factor equal to 0

OpenStudy (anonymous):

[x = -(1/6)*Pi], [x = -(1/2)*Pi]

OpenStudy (mertsj):

I hate it when someone just spouts out the answers.

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