Question

Solve on the interval [0,2pi):

2sin^2(x)+3sinx+1=0

A. x=pi,x=2pi/3,x=5pi/3
B. x=2pi,x=pi/3
C. x=3pi/2,x=7pi/6,x=11pi/6
D. x=2pi,x=pi/4,x=5pi/4

Answer 1

factor it and set each factor equal to 0

Answer 2

[x = -(1/6)*Pi], [x = -(1/2)*Pi]

Answer 3

I hate it when someone just spouts out the answers.