how do I solve, What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = –16
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OpenStudy (anonymous):
a*r^0+a*r^1+a*r^2
1 2 3
notice a patter?
OpenStudy (anonymous):
your a is 1024
OpenStudy (anonymous):
huh?
OpenStudy (anonymous):
a4 will be a*r^3 =-16
1024*r^3=-16 SFr
and plug r back into 6th term which will be
a*r^5
1024*(r you found above)^5 :)
OpenStudy (anonymous):
whats r? haha(:
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OpenStudy (anonymous):
r=-1/4
so
1024*(-1/4)^5
OpenStudy (anonymous):
-1?
OpenStudy (anonymous):
it is actually -1/4
OpenStudy (anonymous):
your r
OpenStudy (anonymous):
-1 is your answer yes :D
lol sorry
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OpenStudy (anonymous):
See you can do it ;)
OpenStudy (anonymous):
haha thanks so I know its the same type of problems but they confuse me so, can you help me with What is the 8th term of the geometric sequence where a1 = 625 and a3 = 25? pleaseee(:
OpenStudy (anonymous):
sure :)
OpenStudy (anonymous):
thank youu!!(:
OpenStudy (anonymous):
a*r^0+a*r^1+a*r^2
1 2 3
625 is your a
625*r^2=25 sfr
then
625*(r you solved for)^7
;)
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OpenStudy (anonymous):
r is 1/5 :) can you take it from here?
OpenStudy (anonymous):
.008?
OpenStudy (anonymous):
YES
OpenStudy (anonymous):
thank you!!(: your soo helpful(:
OpenStudy (anonymous):
So long as you know how to do it :D and notice the pattern
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OpenStudy (anonymous):
a*r^0+a*r^1+a*r^2
1 2 3
notice how the r^n is just -1 the nth term
OpenStudy (anonymous):
r^0 r^1 r^2 r^3
n1 n2 n3 n4
ooh ni is always a your starting a.
cause a*r^0 =a
r^0 = 1 so it is just a * 1= a