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4-8+16-32..., n=7 evaluate the geometric series
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Well, first find the common ratio, which is 2. Your first term is 4 so your equation is \[{(-1)^{n-1}}4 (2)^{n-1}\]
\[8^{3}\] or 512
nope, exponential always comes first so \[4 \times 2^6\]
so256
should be just check by plugging in the values for n: n=1 should be 4, n=2 should be -8, n=3 should be 16 etc
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oh, and because the -1 and 2 both have exponents of n-1, you can combine them
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