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OpenStudy (anonymous):

4-8+16-32..., n=7 evaluate the geometric series

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OpenStudy (roadjester):

Well, first find the common ratio, which is 2. Your first term is 4 so your equation is \[{(-1)^{n-1}}4 (2)^{n-1}\]

OpenStudy (anonymous):

\[8^{3}\] or 512

OpenStudy (roadjester):

nope, exponential always comes first so \[4 \times 2^6\]

OpenStudy (anonymous):

so256

OpenStudy (roadjester):

should be just check by plugging in the values for n: n=1 should be 4, n=2 should be -8, n=3 should be 16 etc

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OpenStudy (roadjester):

oh, and because the -1 and 2 both have exponents of n-1, you can combine them

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