I am trying to find the Laplace Inverse of (s+2)/(s-1)

I know 1/(s-1) is e^t but what is laplace inverse (s+2)/1 ? or should I not split the denom and numerator up?

Thanks

Question

I am trying to find the Laplace Inverse of (s+2)/(s-1)

I know 1/(s-1) is e^t      but what is laplace inverse (s+2)/1 ?  or should I not split the denom and numerator up?

Thanks

turingtest · Answer

can't we do some long division here?

turingtest · Answer

$$\frac{s+2}{s-1}=1+\frac3{s-1}$$

anonymous · Answer

I did expand and did got (3/(s-1)) + 1 if that is what you meant

turingtest · Answer

that is the only answer I see, and it will yield the delta function

turingtest · Answer

I look at it like polynomial long division|dw:1338158620623:dw|