Question

solve equaion

Answer 1

\[\sqrt{7-r}=\sqrt{r-1}\]

Answer 2

if:\[\sqrt{x}=\sqrt{y}\]then you can say:\[x=y\]use this to solve your problem.

Answer 3

i dont get it

Answer 4

if square root of one thing is equal to the square root of another thing, then the two things must be equal.

Answer 5

still need help?

Answer 6

yes

Answer 7

ok, what is \(\sqrt{16}\)?

Answer 8

4

Answer 9

correct, and what is \(\sqrt{8+8}\)?

Answer 10

16

Answer 11

no

Answer 12

\[\sqrt{16}\]

Answer 13

correct - which is 4

Answer 14

so we can say:\[\sqrt{16}=\sqrt{8+8}\]which means:\[16=8+8\]

Answer 15

now, in your case, we have:\[\sqrt{7-r}=\sqrt{r-1}\]therefore we can say:\[7-r=r-1\]

Answer 16

can you solve from here now?

Answer 17

yes

Answer 18

great!