factor completely. 6a^2 - 44ab + 14b2

(2*(3*a-b))*(a-7*b)

can you help me complete this step by step

6a^2 - 44ab + 14b^2

Well if you want to factor out you will need to set it up into two parentheses that look like this ( ) * ( )

The first two values of each parantheses will make up the first term 6a^2 So we know that on each one will have an a because if we multiply them together we get a^2 but we need the 6 right. Well one thing we can do is have the 6 on one side and the other one 1 (6a )*( a ) there we get 6a^2

next is the b and ab Again the last two terms we do for the 14b^2 choose two values that will make 14 b^2 we have a hint that we need b on each side to get the b^2 but we need the 14.

do i use the b^2 or do i use the two values the go into 14

I'm sorry it's really hard for me to explain this. Wait until someone who can do a better job at it.

okay

6a^(2)-44ab+14b^(2) Factor out the GCF of 2 from 6a^(2)-44ab+14b^(2). 2(3a^(2)-22ab+7b^(2)) Find the factors such that the product of the factors is the trinomial 3a^(2)-22ab+7b^(2). This can be done by trial and error and checked using the FOIL method of simplifying polynomials. 2(3a-1b)(a-7b)

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