Question

Solve. x=log[2](1/128)

Answer 1

first write 128 as a power of 2 - what do you get?

Answer 2

163834

Answer 3

i mean 16384

Answer 4

? - so you are saying that:\[2^{16384}=128\]

Answer 5

you need to find a value for n such that:\[2^n=128\]what is n?

Answer 6

oh...

Answer 7

7

Answer 8

correct, now can you use this result to express 1/128 as a power of 2?
i.e. find n such that:\[2^n=\frac{1}{128}\]

Answer 9

2^-1/7=1/128 ??

Answer 10

not quite, what you have found is:\[2^{-1/7}=\frac{1}{\sqrt[7]{2}}\]

Answer 11

how??

Answer 12

\[x^{\frac{1}{a}}=\sqrt[a]{x}\]

Answer 13

so the answer is 7square root of x?

Answer 14

therefore:\[x^{-\frac{1}{a}}=\frac{1}{\sqrt[a]{x}}\]

Answer 15

no, what I had asked you to do was to find n such that:\[2^n=\frac{1}{128}\]

Answer 16

you correctly found that:\[2^7=128\]

Answer 17

ok...i think i get it now. Thanks for your help!!!

Answer 18

yw

Answer 19

\[\log_2\frac{ 1 }{ 128 }=x\\ (128)^{-1}=2^x\\ 2^{-7}=2^x\\\\ -7=x \]