Mathematics OpenStudy (anonymous):

Solve. x=log(1/128) OpenStudy (asnaseer):

first write 128 as a power of 2 - what do you get? OpenStudy (anonymous):

163834 OpenStudy (anonymous):

i mean 16384 OpenStudy (asnaseer):

? - so you are saying that:$2^{16384}=128$ OpenStudy (asnaseer):

you need to find a value for n such that:$2^n=128$what is n? OpenStudy (anonymous):

oh... OpenStudy (anonymous):

7 OpenStudy (asnaseer):

correct, now can you use this result to express 1/128 as a power of 2? i.e. find n such that:$2^n=\frac{1}{128}$ OpenStudy (anonymous):

2^-1/7=1/128 ?? OpenStudy (asnaseer):

not quite, what you have found is:$2^{-1/7}=\frac{1}{\sqrt{2}}$ OpenStudy (anonymous):

how?? OpenStudy (asnaseer):

$x^{\frac{1}{a}}=\sqrt[a]{x}$ OpenStudy (anonymous):

so the answer is 7square root of x? OpenStudy (asnaseer):

therefore:$x^{-\frac{1}{a}}=\frac{1}{\sqrt[a]{x}}$ OpenStudy (asnaseer):

no, what I had asked you to do was to find n such that:$2^n=\frac{1}{128}$ OpenStudy (asnaseer):

you correctly found that:$2^7=128$ OpenStudy (anonymous):

ok...i think i get it now. Thanks for your help!!! OpenStudy (asnaseer):

yw OpenStudy (anonymous):

$\log_2\frac{ 1 }{ 128 }=x\\ (128)^{-1}=2^x\\ 2^{-7}=2^x\\\\ -7=x$

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