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solve for 0<θ<2(3.14[pi]): 9cos^((2))θ-2cosθ-3=0 give answer in terms of 3.14[pi]
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Treat \(\cos \theta\) as if it were a variable and apply the Quadratic formula.
how so i have beeen struggling wit this question all night
Just as normal.\[\cos \theta = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
and then wer do i go from here its a 6 points question
What do you get as \(\cos \theta\)?
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cos theta=-29(-+)square root of 4+108
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