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Mathematics
if logb(3)=.23 and logb(8)=.71, find logb24
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Hint: log(24) = log(3*8) = log(3)+log(8) for any base
i'm supposed to round the answer to the nearest thousandth. how do i get that from this?
log(3) is what?
2
?
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they give it as 0.23
I'm not including the base, but I'm implying log(3) means "log base b of 3"
i don't know
log(24) = log(3)+log(8) log(24) = 0.23 + 0.71 <<--- these are given at the top log(24) = 0.94
than...i really need to review the formulas, because i really do not understand algorithms.
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thanks...
The idea I was using at the top was that log(xy) = log(x)+log(y)
you're welcome
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