The numerator of a fraction is 8 times the denominator. If 5 is subtracted from the numerator, and added to the denominator, the resulting fraction is equal to 11/2. Find the original fraction.

\[ n=8d\\ \frac{n-5}{d+5}=\frac{11}{2} \]

So we can multiply both sides of the second equation by \(d+5\), to get \(n-5=\frac{11}{2}(d+5)\). So then \(n=\frac{11}2d+\frac{55}2+5,\ 2n=11d+60,\ 16d=11d+60,\ 5d=60\)... can you solve it from there?

This method might be ahead of what you've learned so far.

...I don't recognize it so that seems most likely 'x3

What method did you use to solve problems like this in class?

Online course with glitchy slideshows that don't explain things well... . _ .''

What course is it? Which grade, or what math level?

I'm in 12th but I failed part of Algebra freshman year and the just told me like...a month ago that I needed to make it up ~ _ ~''

Okay, this is something you should know then. This is basic algebra. You make a variable to represent the numerator, which I called \(n\), and a variable to represent the denominator, which I called \(d\), and then you write the word problem out using equations.

Join our real-time social learning platform and learn together with your friends!