What is the probability of rolling a sum of 8 on at least one of two rolls of a pair of number cubes?

from 1 to 6 ..what pairs add up to 6 ? i'll start with it,,you continue.. (2,6), (3,5) ... ??

idk omggggg imma fail -______-

comeon,,you cant be dumber than me! ;) just tell me a pair of 2 nos between 1 and 6 that add up to 8..whats the big deal?

i'm not getting what you are saying. i'm seriously getting frustrated haha..

guys, could you help me on this one? get the common ratio if the 4th and 7th term of a geometric sequence is -4 and 108, respectively. I badly seek for the answer.. please show the formula. :)

hmmn,,i think you should take some rest and try all this later @katelynx3 ..it'll be of no use if i/or anyone else simply tells you the ans..hmmn..

yeah it will be! but ugh k.

btw, 2 pairs of nos. that can sum up to8.. (1,7) (2,6) (3,5) (4,4) :)

@lovelyDee the nth term of a GP is ar^(n-1) a=1st term,,r is common ratio..and n is term no.. hope this helps and by the way,,altough the listed the pairs right,,but mind you,,7 doesnt come on a dice,,unless you use some out of this world dice,, l)

@shubhamsrg ohh. :)) i didn't get to read that "dice" part.. :) so i was hoping to type all those possible nos. :)

@katelynx3 yes I'm still here.. :)

message me back please! (:

There are 36 possibilities. Probability of rolling a sum of 8 here is in these cases: {6,2}{5,3}{4,4}{3,5}{2,6}

.. what is the 13th term in an arithmetic sequence whose 1st term is is 10, and whose 4th term is 1?? please.. i just need the answer and the formula to get it. ty!! :)

Common difference is -3. The formula for nth term in an arithmetic sequence is: \(a_n = a_1 + (n - 1)d\) So, \(\Large \color{Black}{\Rightarrow a_{13} = 10 + -3(13 - 1)}\) \(\Large \color{Black}{\Rightarrow a_{13} = 10 + -3(12) }\) \(\Large \color{Black}{\Rightarrow a_{13} = 10 - 36 }\) \(\Large \color{Black}{\Rightarrow a_{13} = -26 }\)

ohh! thank you!! well I am just curious.. how did you get the common difference?.. represented by "d"? :)

Because you're adding -3 every time :)

ohh.. so you used a little of common sense to get it. right?? ;)

Lol yeah

okaaay. thanks so much. :)

@ParthKohli uhm how abt this one.. how many integers between 65/9 and 2024/9 are exactly divisible by 7?? :))

\(\Huge \color{Black}{\mathfrak{<tips hat>} }\)

65/9 is approximately 7.something 2024/9 is approximately 224.something You can count now..

It'll start at 14 and end at 224.

i think its 31.. am i right??

7 * 2 = 14 7 * 32 = 224 31 numbers. Correcto!

yey!! :)

how about this one??... if the first 2 terms of a geometric progression are \[4x ^{2}\] and 3/y, then the third term is...??

Hmm.. see the common ratio

\(\Large \color{Black}{\Rightarrow {4x^2 \over 3\div y } }\) is the common ratio. Multiply this to 3/y to get the next one.

then i get...9/\[4x ^{2}y ^{2}\].... ??? right?

ok... ty for this!!! :)

Lol \(\Huge \color{orange}{<tipshat - again>}\)

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