Question

attached

Answer 1

\[\sqrt{\left(\begin{matrix}64x^3 \\ 81y^7\end{matrix}\right)}\]

Answer 2

\[\sqrt{\left(\begin{matrix}64x^3 \\ 81y^7\end{matrix}\right)}=\sqrt{\left(\begin{matrix}8^2x^2\times x \\ 9^2(y^3)^2\times y\end{matrix}\right)}=\sqrt{\left(\begin{matrix}(8x)^2\times x \\ (9y^3)^2\times y\end{matrix}\right)}\]can you solve from here?

Answer 3

use the rule:\[\sqrt{a^2\times b}=a\sqrt{b}\]

Answer 4

so then....\[\left(\begin{matrix}8x^2 \sqrt{x} \\ 9y^3\sqrt{y}\end{matrix}\right)\]

Answer 5

almost...

Answer 6

but then do i have to rationalize the denominator?

Answer 7

the top term should be \(8x\sqrt{x}\) and not \(8x^2\sqrt{x}\)

Answer 8

this is a matrix - not a fraction, so no rationalization required

Answer 9

oh.....okay.

Answer 10

so.....\[\left(\begin{matrix}8x \sqrt{x} \\ 9y^3\sqrt{y}\end{matrix}\right)\]

Answer 11

thats it - correct

Answer 12

thank you!