Question

64^(x-4)=4^2x can someone please explain to me how to solve this

Answer 1

\[\large 64= 4^3\]\[\Large ((4)^3)^{(x-4)}= 4^{2x}\]\[\Large 4^{3(x-4)}=4^{2x}\]

Therefore
3(x-4) = 2x
can you do it now?

Answer 2

yeah but that first part confuses me can you tell me like what you did

Answer 3

ok 64 = 4^3

So inorder to make the bases same i replaced 64 with 4^3

Now we know that\[\Large (x^m)^n=x^{m \times n}\]Same way\[\Large (4^3)^{(x-4)} =4^{3(x-4)}\]

Is this clear ?

Answer 4

yeah thank you!

Answer 5

Anytime :)