Question

A triangle has vertices whose coordinates are A (0, 0), B(5, 7), and C(3, 9). Find the coordinates of the midpoints of each side. Answer in terms of a decimal rounded to the nearest tenth or an improper fraction in simplest form.

Midpoint of AB = (,)

Midpoint of BC = (,)

Midpoint of CA = (,)

Answer 1

To get the midpoint between two points, just figure out the x that is between their x coordinates and the y that is between the y coordinates.
Here's a quick example to show you what I mean.
Point A (0,2) Point B (1, 0)
Their x coordinates are 0 and 1. Exactly between those is 0.5
Their y coordinates are 2 and 0. Exactly between those is 1
So my midpoint is (0.5, 1)

Answer 2

thanks!

Answer 3

You're welcome =) Think you can do this one now? Feel free to ask me any questions.

Answer 4

yeah definately !:)

Answer 5

Midpoint of AB = (5/2, 6)

Midpoint of BC = (6,6)

Midpoint of CA = (6,5/2)


is this right?

Answer 6

No, but I'm not sure what you're doing =/

Answer 7

im using this formula (a+b)/2... given to me in the lesson so idk

Answer 8

That is fine. (a+b)/2 gives you the average, which will be the point exactly between the two, like I told you to find.
But somehow you're doing it wrong because (a+b)/2 will not give you the results you got.

Answer 9

dang:/ ok

Answer 10

what would i do for Midpoint of AB =??

Answer 11

Let's start with just points A and B.
Their x values are 0 and 5
What x value is exactly between those two? You could do (a+b)/2 if you need to.

Answer 12

5/2? thenn right?

Answer 13

Right. Good. 5/2, which is just 2.5. Now look at the y values and do the same thing. Their y values are 0 and 7

Answer 14

7/2........... omg yes i did something wrongg

Answer 15

Yes. 7/2, which is 3.5

Answer 16

So the midpoint for AB is
(2.5, 3.5)
or you could write it as
(5/2, 7/2)

Answer 17

Let me see your try for AC next.