Question

can anyone help with this?

Answer 1

\[b _{7} is b _{n}\] so from here on you see that 7 is n.
You replace 7 for in the in original question then tell me what do you get?

Answer 2

replace 7 for n*

Answer 3

7-1 =6?

Answer 4

@Anhina

Answer 5

so is it going to be 7*6=42?

Answer 6

no

Answer 7

(sigh)

Answer 8

im stupid..

Answer 9

No you are not. Math is another language to 90% of our human population.

Answer 10

see! u understand me! LOL

Answer 11

so can u tell me the answer and explain how you got it? So i can use the explanation for future problems like this

Answer 12

Recalled I suggest you to plug in 7 for n can you write the equation that you got from replacing it for me without solving it?

Answer 13

suggested*

Answer 14

Sorry \[b _{1}=1\] my bad

Answer 15

ok

Answer 16

b*7=7+b(7-1)

Answer 17

Also when you see it like this \[b _{1} \] = 1!

Answer 18

note that \(b_n \) does not mean b*n. It is just a way to label the b Think of it as the nth b.
So the 7th b (written b_7) equals 7 plus the 6th b. Now you have to find what is the 6th b

Answer 19

so you have \[7+b _{6} \] right? because 7 - 1 = 6

Answer 20

can you rewrite b\[b _{6}\] ?

Answer 21

b6=6+1=(6-1)

Answer 22

+b*

Answer 23

to bind b_6 use the formula b_6= 6 + b_5 (replace n with 6)

Answer 24

We got off track a bit lol but it's fine.
Can you rewrite \[7+b_{6}\]

Answer 25

wait so this is going to end up being D isent it?

Answer 26

in the Exclamation form

Answer 27

because this looks liek 7!

Answer 28

Look at the formula. NO MULTIPLICATION.

Answer 29

Only the b can be convert to ! without the b those numbers are normal

Answer 30

so then u guys are saying its either b or c

Answer 31

No guessing here buddy lol

Answer 32

Don't skim through the chat read it word for word

Answer 33

im trying but im kinda on a time frame i have to finish this and 50 more other things like this or i dont graduate i have to turn this in by june 3rd

Answer 34

so all im asking is for the answer and a explanation because at this point i cant learn all the material im going to have to go through in the next 5 days.. :(

Answer 35

Rewrite \[7+b _{6} \]in exclamation form

Answer 36

7+6! ?

Answer 37

@Anhina

Answer 38

@phi

Answer 39

is it 7+6!

Answer 40

Yes.

Answer 41

thanks so much

Answer 42

Remember only the one with b can be convert to !
without the b they are normal numbers. Just like green lantern without his ring he is normal.

Answer 43

Here is what you do
you have a formula
b_n = n + b_(n-1)

to find b_7, replace the n with 7
b_7 = 7 + b_6

this says to find b_7 you add 7 to b_6

Now find b_6

How?
use the formula
b_6= 6 + b_5

to find b_6 add 6 to b_5. What is b_5
use the formula.

Answer 44

keep doing that until you get to b_1 which you know is 1

Answer 45

thanks guys

Answer 46

what did you get?

Answer 47

\[b _{1}=1\]
\[b _{2}=2+b _{1}=2+1=3\]
\[b _{3}=3+b _{2}=3+3=6\]
\[b _{4}=4+b _{3}=4+6=10\]
\[b _{5}=5+b _{4}=5+10=15\]
\[b _{6}=6+b _{5}=6+15=21\]
\[b _{7}=7+b _{6}=7+21=28\]

Answer 48

@phi@Anhina Why isn't the above solution correct?

Answer 49

because it's the terms not the numbers

Answer 50

So b sub n-1 means the product of all the previous terms?

Answer 51

@Mertsj it is correct. b_7= 28
The real trick is getting sktjell to understand how to do it.

Answer 52

Thank you!!! I thought I was going crazy.

Answer 53

So Anhina was incorrect.