Definite integral help please. Can someone please help me. I have x^2(x+2) dx from -2 to 2. To start off with I put u = (x+2) du/dx=x and du/x = dx

Question

Definite integral help please.  Can someone please help me.  I have x^2(x+2) dx from -2 to 2.  To start off with I put u = (x+2) du/dx=x and du/x = dx

mimi_x3 · Answer

$$\int\limits x^{2}(x+2)dx  $$
Just expand it; i don't think u-sub would work.

anonymous · Answer

I wondered that originally because when I tried to u sub it it didn't work lol.  So x^3 + 2x^2

anonymous · Answer

$$x^3+2x^2 = x^3+x^4/2$$

mimi_x3 · Answer

I don't think so..

anonymous · Answer

oh can you please show me the way

mimi_x3 · Answer

$$=>\int\limits x^{3}+2x^{2}dx  => \frac{x^{3+1}}{3+1}  +\frac{2x^{2+1}}{2+1}  +C$$

mimi_x3 · Answer

$$=> \frac{x^{4}}{4}  +\frac{2x^{3}}{3}  +C$$

anonymous · Answer

Thank you

mimi_x3 · Answer

np