Question

A racing dog is initially running at 13.0 , but is slowing down.How fast is the dog moving when its kinetic energy has been reduced by half?

Answer 1

Formula for kinetic energy:
\[ E_k = \frac{1}{2} m v^2 \]
when the kinetic energy is reduced by half, we get
\[ \frac{1}{2}m {v_2}^2 = \frac{1}{2}\frac{1}{2} m {v_1}^2 \]
and the answer is
\[ v_2 = \frac{v_1}{\sqrt{2}} \]

Answer 2

ok i got like this 1/2m (13)sq, when reduced by half i solved for velocity, square root of 84.5 =9.19