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determine the following intergral:(ax + b)^(3/2) dx
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no i dont
ax^(a-1)?
no i am not familiar with it
sorry, i thought , it differentiation....
try let u=ax+b du=adx \[\frac{1}{a}\int\limits u^{3/2} \, du\]
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then just integrate and sub back in
int of x^n dx=x^(n+1)/n+1
how does one intergrate though
Follow @Sam suggestion. He has given u some clue.
Try first
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use this
\[\int\limits_{}^{}(ax+b)^{\frac{3}{2}}dx=\frac{2(ax+b)^{\frac{5}{2}}}{5a}\]
Plus C of course.
This was done by inspection using the standard rule for integration ahd then differentiating to check and adjust the result.
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