A circle its center at the center of a square with 8 inch sides. Find the area of the square not covered by the circle. Round the answer to the nearest tenth.
A) 57.1 in²
B) 9.1²
C) 2.0²
D) 13.7 in²
(Will draw picture below)

Question

A circle its center at the center of a square with 8 inch sides. Find the area of the square not covered by the circle. Round the answer to the nearest tenth.                                                                       
A) 57.1 in²                                                               
B) 9.1²                                                                       
C) 2.0²                                                                      
D) 13.7 in²                                                           
(Will draw picture below)

anonymous · Answer

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anonymous · Answer

The diameter is 8 inches. 

The radius is therefor half of that: 4 inches.

The area that is not covered is the difference between the area of the square and the circle.

area of circle is :
$$\pi r^2$$

area of square is:
$$x*x=x^2$$

where x is a side (8 )

anonymous · Answer

So x * x is 8 * 8 =64² which equals 32 ?

anonymous · Answer

the area of the square is 64....now find the area of the circle now.

anonymous · Answer

Can you help me out on how to find it? I will do the work but idk how to find it.

radar · Answer

Did you understand how romero  got the area of the square?

radar · Answer

A=side X side   Since a square has equal sides, then side squared will work.

radar · Answer

Next find the area of circle, the radius is 1/2 the diameter or 1/2 of 8 or 4
r=4
The area of a circule is$$A=\pi r ^{2}$$ This you should have committed to memory (the area of a circle)
A= pi X 16 sq in.

radar · Answer

Just take the difference of the two area and the problem is solved.