Meh. I don't understand square roots. xD Help, please? I'll type up the problem in the comments.
Nakim simplified \[3\sqrt{2} + x \sqrt{8x} - 5\sqrt{18x}\] and got \[-10x \sqrt{2x}\] for an answer. Explain what Nakim did wrong, and then simply the expression correctly.
sqrts are just like factors; you can treat them as an extra variable if need be
notice that the first one aint got no x in it, so it aint like the others.
I'm confused. :/
im sure you are, but i cant read minds so youll have to be more specific in your condition.
How would I simplify the expressions so I can solve it?
take out the perfect squares that are inside of them
can you list the first few perfect squares? up to 5^2 should suffice for this
Wait, what? D:
what does "wait what" mean???
I don't understand what you're asking me to do. :/
take the first few numbers; 1 - 5 and square them
whgwertgwhrteg;rgje what first few numbers? x.x
I seriously don't understand anything you're asking me to do. :/ I don't understand square roots at all.
apparently you dont understand; first few numbers 1-5 either, or what it means to square them ....
Apparently not. ._.
then your not understanding more than just square roots
Can't you just show me how to simplify one of them and I can use it to help me figure out the other ones? :/
im trying, but you dont understand
a square root undoes a square
what is 3^2 ?
9?
yes, and what is 2^2 ?
4?
good, these will be all we need for this problem; 4 and 9 are called perfect squares since they can be undone by a square root sqrt(4) = 2 sqrt(9) = 3 does this make sense?
does 8x have any perfect square factors?
2 and 4? o.o
yes :) sqrt(8x) = sqrt(4*2x) = sqrt(4) * sqrt(2x) = 2 sqrt(2x) that is the simplified version of sqrt(8x)
does 18x have any perfect square factors?
Oh. The first one is supposed to be 3 sqrt (2x), not 2
we should keep that in mind after we simplify the others then :)
and... 18 has 9 and 2. right?
9 and 2 are correct sqrt(18x) = sqrt(9*2x) = 3sqrt(2x) notice how we can undo a perfect square factor and pull it out
this leaves us with: \[3\sqrt{2x}-x*2\sqrt{2x}-5*3\sqrt{2x}\]
So it would be.. 3 sqrt (2x) + 2 sqrt(2x) - 5 * 3sqrt(2x)
yeah.
yes, but dont forget the "x" term in the middle
oops. o.o
3sqrt(2x) + 2x sqrt(2x) -15sqrt(2x) and the rest is history
So that means my final answer is.. 2x - 12sqrt(2x)?
if yo udo it that way, try using this for the notation (2x - 12) sqrt(2x)
That was my answer before, and my teacher said to "review my final answer." which makes me think that's wrong. :/
its not wrong; but your teacher might want a different format
2x sqrt(2x) - 12 sqrt(2x) is another way to write it
What Nakim did wrong, is he ignored that the second term had a factor of x, and added all the terms together. The real answer would be: 2x - 12sqrt(2x) Response Feedback: Please review your final answer. ^^ that's the response she gave me.
your notation is bad ... put paranthesis around 2x - 12 to keep it as a single value
okay.
thanks. n.n
spose you had: 3n + 2xn -15n 2x -12n is not a proper simplification
True. I think I see what I did wrong. Thanks for the help. :
youre welcome
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