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solve this DE: y'+y=e^{3x}
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\[e^{\int{}{}p(x)dx}\]
\[e^{\int{}{}dx}=e^{x+c}\]
o wait i know what i didn' do
you dont need a contant of integration 'c' in your integrating factor
\[\frac{\text d}{\text d x}(ye^x)=e^x\cdot e^{3x}\]
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yep then i forgot to integrate the right side for some reason. i think it's because the question before was a homogeneous equation
you can finish from here?
yes
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