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(2x^2 + 6x) / (10x^3)
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x+3 over 5x^2
@kymy_rose00 did you understand?
is that all the work?
\[x+3\div5x ^{2}\]
how did you guys get that?
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\[\frac{(2x^2 + 6x) } { (10x^3)}\] To simplify this we need to cancel the common factors from the numerator and the denominator We see that 2x is common in both terms of numerator \[\frac{(2x\times x + 3\times 2x.) } { (10x^3)}\] and 2x is also a factor of the denominator \[\frac{(2x\times x + 3\times 2x.) } { (2x \times 5x^2)}\] Now you cancel 2x from both numerator and denominator!!
thanks
ash your so smart :)
Thanks @Bambi and welcome @kymy_rose00
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