Determine whether the graph of y = −3x2 + 2x − 8 opens up or down and whether it has a maximum or minimum point.
I think it's Down; Minimum?
The graph is pointing down, and it has a MAXIMUM point. An upside-down parabola does not have a minimum because it stretches infinitely downward. However, it does have a maximum, which is its peak since it is upside down.
what about "Determine whether the graph of y = x2 + 2x − 8 has a maximum or minimum point, then find the maximum or minimum value."
Maximum; (-9, -1)?
Lemme do it real quick.
Do you have the formula for min and max or are you using derivatives?
I don't know the formula
Okay, I know how to figure this out. Here, I'll show you.
f(-b/2a) Therefore, you need to plug in -(2)/(2)(1). This equals -1. That is your x-coordinate for the vertex of the parabola, which is its MINIMUM point. To find y, you need to plug in (-1) into the original equation. Like so, (-1)^2 + 2(-1) - 8 = -11. Therefore, the minimum point is (-1, -11)
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