Question

Find the 6th term of the sequence with t1 = -4 and tn = 5^tn-1

Answer 1

t1 = -4 and tn = 5t^n-1 *

Answer 2

You just substitute.

Answer 3

-4 -1?

Answer 4

Can you latexify it please?

Answer 5

huh?

Answer 6

Can you write the question with equation editor?

Answer 7

okay

Answer 8

\[t ^{1} and t ^{n} = ^5{t} n-1\]

Answer 9

5t is squared

Answer 10

not only 5

Answer 11

\(\Large \color{Black}{\Rightarrow t_n = 5^{t - 1} }\)
This?

Answer 12

yeah but with n?

Answer 13

Ok

Answer 14

I get it :D

Answer 15

ok :)

Answer 16

So if n is 2 and (n - 1) is 1, then we can say:

\(\Large \color{Black}{\Rightarrow t_2 = 5^{(t_1)} }\)
\(\Large \color{Black}{\Rightarrow t_2= 5^{-4} }\)

Just keep doing like this.

Answer 17

ok

Answer 18

I think you meant 5 * (tn -1)

Answer 19

Am I right?

Answer 20

yes

Answer 21

So then it's a geometric sequence.

\(\Large \color{Black}{\Rightarrow -4 \times 5^{n - 1} }\)

Here
\(\Large \color{Black}{\Rightarrow -4 \times 5^{6 - 1} }\)

\(\Large \color{Black}{\Rightarrow -4 \times 5^5 }\)

\(\Large \color{Black}{\Rightarrow -4 * 3125 }\)

\(\Large \color{Black}{\Rightarrow -12500 }\)