Question

How many 3-digit passwords can be formed from the digits 0 through 9?

Answer 1

answers
729
900
1,000

Answer 2

This is asking "how many numbers are there from 0 to 999 ? " :)

Answer 3

(remember to include 0)

Answer 4

\[9 \times 10\times 10 =900 \]

Answer 5

why not 1,000?

Answer 6

9 slots for first digit.
10 for second.
10 for third.

9 * 10 * 10

Answer 7

like what tyler said?

Answer 8

so what one

Answer 9

What is 9 * 10 * 10?

Answer 10

The first digit cannot be 0, because then that'll become a 2 digit number

Answer 11

so 900

Answer 12

Yes.

Answer 13

@FoolForMath that is incorrect.

They want all the passwords from

000
through
999

So that's 10 choices for each of the three places. 10^3 = 1000. :)

or just list them all

000
001
002
003
...
997
998
999

Which is 1,000 total codes.

Answer 14

Thanks math teacher!

Answer 15

000 is not 3 digit

Answer 16

Hm, abstruse, depends on the implementation.

Answer 17

It is not clarified whether 000 is 3 digit or 1 digit.

Answer 18

I'm not sure what 001....099 are

Answer 19

lo

Answer 20

There are two ways to interpret this problem.

1) "Three digit codes" means "numbers from 100 to 999".
2) "Three digit codes" means "numbers from 000 to 999".

Answer 21

Yes.

Answer 22

If either 1000 or 900 weren't a choice, then it'd have been solved easily.

Answer 23

They have made it unclear and confusing.

Answer 24

Poorly worded problem.

Answer 25

I chose to interpret it as option 2 because it specifically said codes, and one can set a combination lock or 3-digit passcode as a string of zeros (or 001 etc) if one likes. :)

Answer 26

Nobody can be sure. You may go for 1000 or may not.

Answer 27

ill choose 1000

Answer 28

Yes, I agree with @mathteacher1729, but it depends solely on the implementation.

Answer 29

I go with Mr. Moderator.

Answer 30

This reminds me of a scene from Spaceballs...

http://youtu.be/a6iW-8xPw3k

Answer 31

And in such cases, I will choose not answer this question.