Question

Divide

Answer 1

just flip the values at the bottom then multiply it

Answer 2

can you show me how

Answer 3

goin to to be looking like this:

Answer 4

then what do yuo do

Answer 5

easy the opp of div is multiplication

Answer 6

can you show me again

Answer 7

@summerd are you here?

Answer 8

yesi am here

Answer 9

\[\large \frac{\frac{x^2+2x+1}{x-2}}{\frac{x^2-1}{x^2-4}}\]
Now this division can be converted to multiplication by flipping the denominator
\[\large \frac{x^2+2x+1}{x-2}\times {\frac{x^2-4}{x^2-1}}\]
Do you get this?

Answer 10

ya then what do yuo do

Answer 11

@ash2326 what do you do next

Answer 12

Now let's factor each of the terms
Do you know these?
\[(a+b)^2=a^2+2ab+b^2\]\[(a^2-b^2)=(a+b)(a-b)\]

Answer 13

ya

Answer 14

Use these to factor the terms :)

Answer 15

can you show me how

Answer 16

\[\large \frac{x^2+2x+1}{x-2}\times {\frac{x^2-4}{x^2-1}}\]
We notice that
\[x^2+2x+1=(x+1)^2\]
Do you agree with this?

Answer 17

yes i agree

Answer 18

and
\[x^2-4=(x+2)(x-2)\]
now factor the terms left if they could be factored and then post what do you get

Answer 19

so factor\[ x{2}-4\]

Answer 20

\[\large \frac{(x+1)^2}{x-2}\times {\frac{(x+2)(x-2)}{x^2-1}}\]
now factor \(x^2-1\)?

Answer 21

how

Answer 22

Use the formula
\[(a^2-b^2)=(a+b)(a-b)\]
here we have
\[x^2-1=x^2-1^2\]

Answer 23

and that is the answer oro can you simplify the x to the second

Answer 24

we'll get to the answer, could you factor this?
x^2-1

Answer 25

how to you factor it

Answer 26

@summerd If we have the form
\[(a^2-b^2)\ \text {We factor it as}\ (a+b)(a-b)\]
Now you try factoring it?

Answer 27

Yeah you're right:D

Answer 28

so then what do we do

Answer 29

\[\large \frac{(x+1)^2}{x-2}\times {\frac{(x+2)(x-2)}{(x-1)(x+1)}}\]
Can you simplify it by cancelling the common terms?

Answer 30

can you show me again

Answer 31

\[\large \frac{(x+1)^2}{\cancel {x-2}}\times {\frac{(x+2)\cancel{(x-2)}}{(x-1)(x+1)}}\]
Now cancel other terms like this?

Answer 32

what else do you do can you show me it is hard to draw it

Answer 33

what else do you do can you show me it is hard to draw it

Answer 34

Ok don't draw, do you see any other common terms in numerator and denominator?

Answer 35

x+1

Answer 36

Yeah so we'll get \[\large {(x+1)^\cancel 2}\times {\frac{(x+2)}{(x-1)\cancel{(x+1)}}}\]
Tell what's the answer? just type here, don't draw