Question

Can someone please help me with this problem?
(8x/x^2-4)/(4x^2/x^2+4x+4)

Answer 1

\[\large \frac{8x}{x^2-4}/\frac{4x^2}{x^2+4x+4}=\frac{8x}{x^2-4}\times\frac{x^2+4x+4}{4x^2} \]

Answer 2

try factorizing

Answer 3

I already tried, I have no idea what to do.

Answer 4

8*(x+2)^2/4x*[(x^2)
-4]

Answer 5

Hint: \[x^2-c^2 = (x+c)(x-c)\]

Answer 6

\[8*(x+2)^2/4x^3-16x\]

Answer 7

\[x^2+4x+4=(x+a)(x+b)\]where a and b are integers where (a + b) = 4 and ab = 4.

Answer 8

what's the answer?

Answer 9

try finding it yourself.

Answer 10

hold on

Answer 11

\[x^2+4x+4=(x+2)^2\]

Answer 12

\[x^2-4=(x+2)(x-2)\]

Answer 13

\[8*x*(x+2)^2/(x^2-4)*4x^2=2(x+2)^2/x*(x^2-4)\]

Answer 14

\[2*(x+2)^2/x*(x+2)(x-2)=2*(x+2)/x(x-2)\]

Answer 15

understand*

Answer 16

`yep